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Course contents

  • How to Use This Course
  • Reading Path
  • STA Glossary
  • STA Metrics Reference
  • STA Mastery Cheatsheet
  • Timing Paths and Checks16
  • Constraints & SDC Fundamentals20
  • Delay Graph & Path Analysis16
  • Beyond Setup and Hold16
  • Multi-Corner Multi-Mode Signoff16
  • OCV, AOCV, POCV and Variation16
  • Crosstalk and Noise16
  • ECO and Closure16
  • STA Debug Playbook16
    • Constraint Bug Patterns
    • View Mismatch Triage
    • Path Group War Room
      • Daily Triage
      • Owner Assignment
      • Escalation and Signoff Risk
      • Closing the Long Tail
    • Signoff Regression Hygiene
  • STA Interview Prep26
  • Capstone Timing Signoff Lab4
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‹Path Group War Room
  1. Topics
  2. Static Timing Analysis
  3. STA Debug Playbook
  4. Path Group War Room
  5. Owner Assignment

Part 9 · Debug Playbook · All levels

Owner Assignment

Assign each failing endpoint to an owner by the longest matching hierarchy prefix; anything unmatched goes to a default owner and is reported as an orphan.

On this page

    Why it matters

    Violations in a large design belong to blocks, and blocks have owners. Automatic assignment by hierarchy prefix saves time and shows who carries the load. Endpoints that match no rule are orphans; they are the ones nobody will look at unless the process makes them visible.

    Worked example

    example.py
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    rules = {"core/alu": "alu owner", "core": "core owner", "mem": "memory owner", "io": "io owner"}
    default = "integration owner"
    endpoints = ["core/alu/r1", "core/lsu/r7", "mem/ctrl/q3", "io/pad/d2", "top/glue/x1", "core/alu/r9", "mem/ctrl/q8", "top/misc/m4"]
    def owner(path):
        best = None
        for prefix in rules:
            if path == prefix or path.startswith(prefix + "/"):
                if best is None or len(prefix) > len(best):
                    best = prefix
        return (rules[best], False) if best else (default, True)
    assigned = {e: owner(e) for e in endpoints}
    load = {}
    for e, (o, orphan) in assigned.items():
        load[o] = load.get(o, 0) + 1
    orphans = sorted(e for e, (o, orphan) in assigned.items() if orphan)
    assert load == {"alu owner": 2, "core owner": 1, "memory owner": 2, "io owner": 1, "integration owner": 2}
    assert orphans == ["top/glue/x1", "top/misc/m4"]
    print("PASS: load by owner", load, "; orphans (no matching rule)", orphans)

    Owner

    Endpoints

    ALU owner

    2

    Core owner

    1

    Memory owner

    2

    IO owner

    1

    Integration owner (default)

    2 (both orphans)

    Two endpoints go to the alu owner, one to the core owner, two to memory, one to IO. Two endpoints under top/ match no rule and fall to the integration owner as orphans. The longest-prefix rule lets the specific rule (core/alu) override the general one (core): core/alu/r1 and core/alu/r9 go to the alu owner while core/lsu/r7 stays with the core owner. The orphan list is short and visible: either a rule is missing, or the endpoint genuinely belongs to integration; both outcomes are decisions, not accidents.

    What the review looks for

    • Rules are reviewed when the hierarchy changes; stale prefixes silently send endpoints to the wrong owner.

    • The load per owner is shown daily, so one person is not buried while another is idle.

    • Orphans are reviewed first: each gets a rule or an explicit owner.

    Common pitfall

    Assigning by who found the violation. The finder is not necessarily the person who can fix it.

    Interview

    Describe longest-prefix assignment and why orphans are reported separately.

    Check yourself What happens to an endpoint called core/alu/r1 if both 'core' and 'core/alu' rules exist?

    It goes to the alu owner under 'core/alu', the longest matching prefix, not the core owner.

    Related topics

    • Daily Triage

    • Next: Escalation and Signoff Risk

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    See also

    • Closing the Long Tail