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Course contents

  • How to Use This Course
  • The NanoSoC Tour
  • Reading Path
  • SoC Glossary10
  • SoC Metrics Reference
  • SoC Cheatsheet
  • What SoC Integration Is12
  • Architecture and Budgets21
  • Memory Maps and Address Decode26
  • Interconnect and Bus Fabrics26
  • Clock and Reset Architecture24
  • Power Architecture21
  • Interrupts, DMA and Peripherals15
  • Memories, Boot and Security21
  • IP Integration and Handoff21
  • Top-Level Verification and Bring-up21
  • Package, Pads and I/O18
    • I/O Ring and Pad Types
    • Pad Count and Simultaneous Switching
    • Package and Ballout
      • Package Types at a Conceptual Level
      • Ball Assignment Rules
      • Pinout Review and Escape Routing
    • Power Delivery Through Package and Bumps
    • ESD and Latch-Up at the Top
    • Test and Debug Pins (extension)
  • Chip Signoff and Tapeout18
  • SoC Interview Prep16
  • Capstone: Integrate NanoSoC14
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←Package and Ballout
  1. Topics
  2. SoC Design
  3. Package, Pads and I/O
  4. Package and Ballout
  5. Package Types at a Conceptual Level
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    Part 11 of 14, lesson 7 of 18Part 11 of 14/Package, Pads and I/O/Lesson 7 of 18All levels

    Package Types at a Conceptual Level

    Wire-bond versus flip-chip, leaded versus array, and the NanoSoC teaching choice with its costs.

    Why it matters

    What is a package for, which families exist, and why does NanoSoC use the one it does? Ball rules are the next lesson; supply paths through the package are the next topic. The package matters first because it fixes two budgets at once: the number of balls available for the 31 pads, and the inductance of every supply path the noise and power lessons compute with.

    The core idea

    Packages divide along two axes. The die connection is either wire-bond, with thin wires from a ring of pads at the die edge to the package, or flip-chip, with bumps across the die face mated straight to the package. Wire-bond suits low pin counts and low cost and matches a perimeter pad ring; every supply goes through a wire with real inductance. Flip-chip suits higher counts and better power delivery, because bumps are short and supplies can sit beside their consumers, at the cost of bump planning across the die and a redistribution layer if the I/O cells stay in a ring. The board connection is either leaded at the perimeter or an array of balls underneath: perimeters are cheap and inspectable, arrays carry more balls in less area and escape through via channels the third lesson prices.

    NanoSoC's teaching choice is a small leadless ball-array package with the die wire-bonded from a perimeter pad ring. It matches the ring the first topic drew and the perimeter arithmetic of the pad-count topic, and with only 31 pads and a core-limited die there is no pressure that would justify flip-chip. Flip-chip stays in the table as the rejected option, and the lessons on power delivery show what the choice costs in supply inductance. The table compares the families at the concept level; no number in it describes any vendor's product.

    Family

    Die connection

    Board connection

    When it fits

    What it costs

    Wire-bond, leaded perimeter

    Edge wires

    Leads

    Few pins, cost-driven chips

    High supply inductance; no array density.

    Wire-bond, ball array (NanoSoC teaching choice)

    Edge wires from a perimeter ring

    Full ball array

    Modest pin count, board density wanted, die set by the core

    Wire inductance on every supply; pads limited to the perimeter.

    Flip-chip, ball array (rejected)

    Face bumps

    Full ball array

    Power integrity or pin count dominates

    Bump map planning; package cost above wire-bond; pays off only when the perimeter limits the die.

    A note on inductance: from die to package the connection is a bond wire (about a nanohenry, the larger) or a flip-chip bump (tens of picohenries). The package traces and the ball add to either, and the next topic prices them. NanoSoC's supply pairs therefore sit as close to the die as the ring allows, and the decoupling lesson puts capacitors beside them.

    example.py
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    import math
    PADS, EXTENSION = 31, 7                   # NanoSoC v1 pads; optional test and boot pins
    def smallest_array(pads):
        n = math.ceil(math.sqrt(pads))
        return n, n * n
    
    n, balls = smallest_array(PADS)
    assert (n, balls) == (6, 36), (n, balls)
    spare = balls - PADS
    assert spare == 5 and round(100 * spare / balls, 1) == 13.9
    assert not PADS <= 5 * 5                              # a 5 x 5 = 25 ball array cannot hold 31 pads
    n2, balls2 = smallest_array(PADS + EXTENSION)
    assert (n2, balls2) == (7, 49), (n2, balls2)           # the extension forces a bigger array
    print("PASS: 31 pads fit a 6 x 6 = 36 ball array with 5 spare (13.9%); 5 x 5 fails; with 7 extension pads 7 x 7 = 49")

    What the review looks for

    • The package family named with the reason: which budget (pins, power integrity or cost) decided it.

    • Ball count covering all pads plus spares, with the spare balls listed.

    • The inductance of the die connection acknowledged wherever a lesson assumes a short supply path.

    Verify and debug

    Verify the fit on paper: pads plus no-connect balls must fit the array, with a few spare sites left for a later respin. If the array overflows, the choice is a bigger array or fewer pins, never tighter escape channels, which belong to the board team to approve, not the chip team to assume.

    A package ballout error from a pin map the board cannot route: the chip database and the board netlist disagree on one ball, and a board is built wrong. The package choice sets the size of that risk (a perimeter forces the escape outward, an array forces via channels), and the third lesson runs the review that catches it.

    If asked wire-bond versus flip-chip, answer in supply paths and die size: wire inductance and a perimeter-limited die against short bumps and bump planning. Cost follows the physics, not the other way round.

    Check yourself Why does the teaching configuration choose wire-bond for NanoSoC rather than flip-chip?

    Because the die is core-limited with a perimeter that holds the 31 pads with room to spare, so nothing forces area-array bumps, and a wire-bonded ring is cheaper and matches the ring drawn in the first topic. A chip whose perimeter limited its die, or whose supply noise could not be met with wires, would choose flip-chip.

    Related topics

    • Next: Ball Assignment Rules

    • Physical Design: Bump Map and Package Interface

    • Protocols: High-Speed I/O

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    See also

    • Pinout Review and Escape Routing